SOLUTION: x^2+2x+y^2-6y+6=0 Is it a Parabola, cirlcle, ellipse or hyperbola and whats the vertex/center

Algebra ->  Trigonometry-basics -> SOLUTION: x^2+2x+y^2-6y+6=0 Is it a Parabola, cirlcle, ellipse or hyperbola and whats the vertex/center      Log On


   

Question 390496: x^2+2x+y^2-6y+6=0 Is it a Parabola, cirlcle, ellipse or hyperbola and whats the vertex/center
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,        

x^2+2x+y^2-6y+6=0    |completing the squares

(x+1)^2 - 1 + (y-3)^2 -9 + 6 = 0

 (x+1)^2 + (y-3)^2 -4 = 0

 (x+1)^2 + (y-3)^2 = 2^2

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2

where Pt(h,k) is the center and r is the radius

Center of the circle is Pt(-1,3)   (with radius of 2)