SOLUTION: Solve the triangle for little a GIven: <A 60 degrees <B 45 Degrees b=6

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Question 390447: Solve the triangle for little a GIven:
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
By the law of sines,

a%2F%28sin+A%29+=+b%2F%28sin+B%29

Note that sin A = sin 60 = sqrt%283%29%2F2 and sin B = sin 45 = sqrt%282%29%2F2. Replacing all the known values in,

a%2F%28sqrt%283%29%2F2%29+=+6%2F%28sqrt%282%29%2F2%29 Cross multiply:

a%2Asqrt%282%29%2F2+=+6sqrt%283%29%2F2+=+3sqrt%283%29

a+=+6%2Asqrt%283%29%2Fsqrt%282%29+=+3sqrt%286%29