SOLUTION: How do i do (x-2)^2 over 4x^2 - 16 divided by 21x over 3x+6

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Question 390329: How do i do (x-2)^2 over 4x^2 - 16 divided by 21x over 3x+6
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How do i do (x-2)^2 over 4x^2 - 16 divided by 21x over 3x+6
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[(x-2)^2/(4x^2-16)]/[21x/(3x+6)]
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Factor where you can:
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= [(x-2)^2/(4(x-2)(x+2)]/[21x/(3(x+2)]
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Cancel where you can to get:
= [(x-2)/(4(x+2)]/[7x/(x+2)]
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Invert the denominator and multiply:
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= [(x-2)/(4(x+2)]
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Cancel where you can to get:
= [(x-2)/4]
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Multiply to get:
= (x-2)/(28x)
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Cheers,
Stan H.
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