SOLUTION: How do I graph f(x)=(x^2+x-6)/(x^2+2x-8)?
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Question 390264
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How do I graph f(x)=(x^2+x-6)/(x^2+2x-8)?
Answer by
robertb(5830)
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Domain = R\{-4, 2}. Then
.
There is a "hole" in the graph at the point (2, 5/6).
Vertical asymptote: x = -4,
Horizontal asymptote: y = 1,
x-intercept: -3,
y-intercept: 3/4.