SOLUTION: i need help in solving log(base 3)x+log(base 3)(2x)-log(base 3)(x+3)=1

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Question 390118: i need help in solving log(base 3)x+log(base 3)(2x)-log(base 3)(x+3)=1
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
log(base 3)x+log(base 3)(2x)-log(base 3)(x+3)=1
log%283%2Cx%29+%2B+log%283%2C2x%29+-+log%283%2C%28x%2B3%29%29+=+1
log%283%2C%28x%2A2x%2F%28x%2B3%29%29%29+=+1
x*2x/(x+3) = 3
2x%5E2+=+3x+%2B+9
2x%5E2+-+3x+-+9+=+0
(2x + 3)(x - 3) = 0
x = 3
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x = -3/2 *** has to be rejected since you can't take a log of a negative number.