SOLUTION: Solve the equation to find all possible values of y: 2y^2 + 8y + 1 = (y + 3)^2

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Question 39010: Solve the equation to find all possible values of y:
2y^2 + 8y + 1 = (y + 3)^2
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
2y^2 + 8y + 1 = (y + 3)^2
2y^2 + 8y + 1 = y^2 + 6y + 9
y^2 + 2y - 8 = 0
(y + 4)(y - 2) = =
y = -4 or y = 2