SOLUTION: please help me solve for x! :

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Question 389943: please help me solve for x! :
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
log%28v%2C+%282%28x+%2B+1%29%29%29+=+3
To solve for a variable that is in the argument of a logarithm, like x is here, we rewrite the equation in exponential form. In general log%28a%2C+%28b%29%29+=+q is equivalent to a%5Eq+=+b. Using this pattern on your equation we get:
v%5E3+=+2%28x%2B1%29
Now that the logarithm is gone we can solve for x. Start by simplifying the right side:
v%5E3+=+2x%2B2
Subtract 2 from each side:
v%5E3+-+2+=+2x
Divide both sides by 2:
%28v%5E3+-+2%29%2F2+=+x