SOLUTION: which quadratic equation has roots 3 + i and 3 - i ? x^2 - 6x + 10 = 0 x^2 - 6x - 10 = 0 x^2 - 6x + 8 = 0 x^2 - 6x - 8 = 0

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: which quadratic equation has roots 3 + i and 3 - i ? x^2 - 6x + 10 = 0 x^2 - 6x - 10 = 0 x^2 - 6x + 8 = 0 x^2 - 6x - 8 = 0       Log On


   

Question 389878: which quadratic equation has roots 3 + i and 3 - i ?
x^2 - 6x + 10 = 0
x^2 - 6x - 10 = 0
x^2 - 6x + 8 = 0
x^2 - 6x - 8 = 0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,  

Using the Quadratic Formula:  

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+   

x^2 - 6x + 10 = 0  x+=+%286+%2B-+sqrt%28+-4+%29%29%2F%282%29+=+3+%2B-+i+

x^2 - 6x - 10 = 0  x+=+%286+%2B-+sqrt%28+76+%29%29%2F%282%29+

x^2 - 6x + 8 = 0  (x-2)(x-4)= 0 or x+=+%286+%2B-+sqrt%28+4+%29%29%2F%282%29+

x^2 - 6x - 8 = 0   x+=+%286+%2B-+sqrt%2868+%29%29%2F%282%29+