|
Question 38982: Joe, Jane, and Bill weigh 40, 70, and 90 lbs. respectively and use a plank 15 ft. long for a teeterboard. Bill sits 3 ft., Jane 5 ft., and Joe 8 ft. from the fulcrum, on the same side. How far must their father, who weighs 188 lbs., sit from the fulcrum to balance his children?
(Not from a book) I got stumped on trying to put this equation together. Thank you for your help.
Found 2 solutions by checkley71, MaxW:
Answer by checkley71(8403)   (Show Source):
Answer by MaxW(2) (Show Source):
You can put this solution on YOUR website! using the equation d1(w1) = d2(w2)
Joe = 40 lbs(8)
Jane = 70 lbs(5)
Bill = 90 lbs(3)
Father = 188 lbs(x)
Therefore
40(8) + 70(5) + 90(3) = 188(x)
320 + 350 + 270 = 188x
940 = 188x divide both side by 188
x = 5
Joe, Jane and Bill's father must seat 5ft from the fulcrum.
|
|
|
| |
