SOLUTION: what is the value of x in: 81^x+2 = 27^5x+4

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Question 389791: what is the value of x in:
81^x+2 = 27^5x+4
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
81 = 3^4
27 = 3^3
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81^x+2 = 27^5x+4
3%5E%284%28x%2B2%29%29+=+3%5E%283%285x%2B4%29%29
4(x+2) = 3(5x+4)
4x+8 = 15x+12
x = -4/11