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Question 389707: 1. IF :
[3 0 -3]
[2 1 0] = 9,
[0 -2 -1]
then find:
[6 0 -3]
[4 1 0]
[0 -2 -1]
2. IF :
[3 0 -3]
[2 1 0] = 9,
[0 -2 -1]
then find :
[3 0 -3]
[(2+0) (1-2) (0-1)]
[0 -2 -1]
Answer by Edwin McCravy(20055)   (Show Source):
You can put this solution on YOUR website!
1. IF :
[3 0 -3]
[2 1 0] = 9,
[0 -2 -1]
then find:
[6 0 -3]
[4 1 0]
[0 -2 -1]
The first column has been multiplied by 2, so the value of
the determinant has been multiplied by 2, so the value of the
determinant is 2x9 or 18
2. IF :
[3 0 -3]
[2 1 0] = 9,
[0 -2 -1]
then find:
[ 3 0 -3 ]
[(2+0) (1-2) (0-1)]
[ 0 -2 -1 ]
The third row has been added to the second row. The value of a determinant is
not changed if a row (resp., column) [or multiple thereof], is added to another
row (resp., column). Therefore the determinant is still 9.
Edwin
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