SOLUTION: In a right triangle sinA= 3/5 and C=17. Find a and b. Be sure to draw a right triangle and letter it properly. (I appreciate the help.)

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Question 389695: In a right triangle sinA= 3/5 and C=17. Find a and b.
Be sure to draw a right triangle and letter it properly.
(I appreciate the help.)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,  





sinA= 3/5 and C=17

Finding a and b

sinA = opp/hyp = a/c = 3/5 =  3*3.4/5*3.4 = 10.2/17

  a = 10.2

Applying Pythagoream Theorem a^2 + b^2 = c^2

b=+sqrt%2817%5E2+-+10.2%5E2%29=+highlight%2813.6%29