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dividing (3x^4-3x^3-6x-10)/(x-2) by using long division
3x^3 + 3x^2 + 6x +6 Remainder = 2
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x-2 | 3x^4 -3x^3 -6x-10
- (3x^4 - 6x^3)
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3x^3
- (3x^3 - 6x^2)
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6x^2 -6x
-(6x^2 -12x)
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6x -10
-(6x -12)
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2
dividing (4x^4-12x^3-48x-60)/(x-4)done in similar fashion resulting in
4x^3 + 4x^2 + 16x + 16 Remainder = 4
As to: Using substitution to determine if an x value results in P(x) = 0
simply use that value of x in the function:
P(1)=3x^4-10x^3-29x^2+16x+20 = 3 -10 -29 + 16 + 20 = (29-29)= 0
As to using substitution to determine whether x-3 is a factor of
4x^4-9x^3-109x^2+225x+225...(x-3) is a factor only if f(3) = 0
f(x) =4x^4-9x^3-109x^2+225x+225
f(3) = 4*81 - 9*27 - 109*9 + 255*3 + 225 = (1224 - 1224) = 0 (x-3) is a factor