SOLUTION: Use the quadratic formula to solve the equations: 0 = x^2 + x - 20 0 = x^2 - 5x + 6

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Question 389612: Use the quadratic formula to solve the equations:
0 = x^2 + x - 20
0 = x^2 - 5x + 6

Found 2 solutions by Edwin McCravy, Earlsdon:
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!

Use the quadratic formula to solve the equations:
0+=+x%5E2+%2B+x+-+20
Write as
x%5E2+%2B+x+-+20=0
and then as
1%2Ax%5E2+%2B+1%2Ax+%2B+%28-20%29=0
and compare to this form which you must memorize:
A%2Ax%5E2+%2B+B%2Ax+%2B+C+=+0
We see that A=1, B=1, C=-20. and we substitute into
this formula which you must also memorize:

x+=+%28-B+%2B-+sqrt%28+B%5E2-4%2AA%2AC+%29%29%2F%282%2AA%29+
x+=+%28-%281%29+%2B-+sqrt%28+%281%29%5E2-4%2A%281%29%2A%28-20%29+%29%29%2F%282%2A%281%29%29+
x+=+%28-1+%2B-+sqrt%28+1%2B80%29%29%2F2+
x+=+%28-1+%2B-+sqrt%2881%29%29%2F2+
x+=+%28-1+%2B-+9%29%2F2+
Use the + for the first solution:
x+=+%28-1+%2B+9%29%2F2+
x+=+8%2F2+
x+=+4 That's the first solution.
Use the - for the second solution:
x+=+%28-1+-+9%29%2F2+
x+=+%28-10%29%2F2+
x+=+-5 That's the second solution.
There are two solutions x = 4 and x = -5.
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The other one is solved the same way.
The solutions to it are x = 3 and x = 2
Edwin

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Use the quadratic formula x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a to solve:
1) 0+=+x%5E2%2Bx-20 Here, a = 1, b = 1, and c = -20, make the appropriate substitutions to get:
x+=+%28-1%2B-sqrt%281%5E2-4%281%29%28-20%29%29%29%2F2%281%29 Evaluate.
x+=+%28-1%2B-sqrt%281-%28-80%29%29%29%2F2
x+=+%28-1%2F2%29%2B-sqrt%2881%29%2F2
x+=+%28-1%2F2%29%2B%289%2F2%29 or x+=+%28-1%2F2%29-%289%2F2%29
x+=+4 or x+=+-5
Use the same approach on the second equation.