SOLUTION: Find the x-intercepts of the parabola with vertex of (-2,-8) and y-intercepts of (0,4).I have no Idea how to solve this please help.

Hi,  

the vertex form of a parabola,  where(h,k) is the vertex

vertex (-2,-8)

y =a(x+2)^2 -8

using y-intercept pt(0,4) to find a

4 = a(-2)^2 -8

12 = 4a

 3 = a

y = 3(x+2)^2 -8  

finding x-intercepts when y = 0

0 = 3(x^2 + 4x + 4) -8 

0 =  3x^2 + 12x + 4





  Present these x values as is traditional for your classroom