Question 389521: solve each system of equations
how doi do this?
x-4y=16
x+2y=4
Answer by haileytucki(390)   (Show Source):
You can put this solution on YOUR website! 1st one
x-4y=16
Since x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting x from both sides.
-4y=-x+16
Divide each term in the equation by -4.
-(4y)/(-4)=-(x)/(-4)+(16)/(-4)
Simplify the left-hand side of the equation by canceling the common factors.
y=-(x)/(-4)+(16)/(-4)
Simplify the right-hand side of the equation by simplifying each term.
y=(x)/(4)-4
x-4y=16
Since -4y does not contain the variable to solve for, move it to the right-hand side of the equation by adding 4y to both sides.
x=4y+16
2nd Problem
x+2y=4
Since x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting x from both sides.
2y=-x+4
Divide each term in the equation by 2.
(2y)/(2)=-(x)/(2)+(4)/(2)
Simplify the left-hand side of the equation by canceling the common factors.
y=-(x)/(2)+(4)/(2)
Combine the numerators of all expressions that have common denominators.
y=(-x+4)/(2)
x+2y=4
Since 2y does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2y from both sides.
x=-2y+4
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