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Question 389457: Find the linear equation in standard or slope intercept form given the points
(-6,-4) (-2,-2)
Could you please show your work so I can figure out where I went wrong!!! Have been working on these for a long time and need a little help.
THANK YOU very much!!!!!
Found 2 solutions by ewatrrr, MathLover1:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi
the standard slope-intercept form for an equation of a line y = mx + b
where m is the slope and b the y-intercept.
finding in slope intercept form
(-6,-4) (-2,-2)
m = [-2-(-4)] /[ -2-(-6)] = 2/4 = 1/2
Slope m = 1/2
y = (1/2)x + b using ordered pair Pt(-2,-2) to solve for b
-2 = (1/2)*-2 + b
-2 = -1 + b
-1 = b
y = (1/2)x - 1
Answer by MathLover1(20850)  (Show Source):
You can put this solution on YOUR website!
here is your answer:
| Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-6, -4) and (x2, y2) = (-2, -2).
Slope a is  .
Intercept is found from equation  , or  . From that,
intercept b is  , or  .
y=(0.5)x + (-1)
Your graph:
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