SOLUTION: the width of a rectangle is 12 units less than the length. the perimeter is 108 units. find the length.

Algebra ->  Parallelograms -> SOLUTION: the width of a rectangle is 12 units less than the length. the perimeter is 108 units. find the length.       Log On


   

Question 389441: the width of a rectangle is 12 units less than the length. the perimeter is 108 units. find the length.
Found 2 solutions by ewatrrr, gwendolyn:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi, 

Let x and (x-12)represent the length and width respectively        



Question states***

 2x + 2(x-12) = 108

solving for x

 4x - 24 = 108

    4x = 132

     x = 33 units, the length



CHECKING our Answer***

  66 + 2*21 = 66 + 42 = 108

Answer by gwendolyn(128) About Me  (Show Source):
You can put this solution on YOUR website!
Let W be the width of the rectangle and L be the length.
We know that the width is 12 units less than the length, so:
W = L - 12
We also know the perimeter is 108 units, so:
2*W + 2*L = 108
Substitute the value for w from the first equation:
2*(L - 12) + 2L = 108
Distribute the 2 on the right and combine the L terms:
2L - 24 + 2L = 108
4L - 24 = 108
Add 24 to both sides:
4L -24 + 24 = 108 + 24
4L = 132
Divide both sides by 4:
L = 33
So, the length is 33 units.