SOLUTION: Twice the first of three consecutive even integers minus the third equals 36. Find the 3 integers.

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Question 389382: Twice the first of three consecutive even integers minus the third equals 36. Find the 3 integers.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Three consecutive even integers: x, (x+2), (x+4)
:
Twice the first of three consecutive even integers minus the third equals 36.
Just write an equation for what it says
2x - (x+4) = 36
Remove brackets
2x - x - 4 = 36
x = 36 + 4
x = 40
:
40, 42, 44 are the integers
:
:
Check in the given statement:
"Twice the first minus the third equals 36. Find the 3 integers."
2(40) - 44 = 36