SOLUTION: a rectangle has a length one foot longer than twice the width. the area of the rectangle is 253 square feet. find the (a) length and (b) width.
can you show me how to do this pr
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-> SOLUTION: a rectangle has a length one foot longer than twice the width. the area of the rectangle is 253 square feet. find the (a) length and (b) width.
can you show me how to do this pr
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Question 389378: a rectangle has a length one foot longer than twice the width. the area of the rectangle is 253 square feet. find the (a) length and (b) width.
can you show me how to do this problem? thanks. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! a rectangle has a length one foot longer than twice the width. the area of the rectangle is 253 square feet. find the (a) length and (b) width.
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the unknowns are the length & width.
but they have a relation.
let width be x feet
length will be 2x+1
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L*W=Area
x(2x+1)= Area
x(2x+1)= 253
2x^2+2x= 253
-253
2x^2+2x-253=0
solve for roots using quadratic equation.
a=2,b=2,c-253
b^2-4ac=2028
width = 10.758 feet
This is negative so it is not practical
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width = 10.76
length = (2x+10
Length = 2*(10.76+1)
Length = 23.52 feet
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CHECK
23.52*10.76=253.07
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m.ananth@hotmail.ca
