SOLUTION: write in standard form an equation of the line that passes through the two points.Use integer coefficients (-1,0)and (3,10)

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Question 389363: write in standard form an equation of the line that passes through the two points.Use integer coefficients (-1,0)and (3,10)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
First let's find the slope of the line through the points and


Note: is the first point . So this means that x%5B1%5D=-1 and y%5B1%5D=0.
Also, is the second point . So this means that x%5B2%5D=3 and y%5B2%5D=10.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%2810-0%29%2F%283--1%29 Plug in y%5B2%5D=10, y%5B1%5D=0, x%5B2%5D=3, and x%5B1%5D=-1


m=%2810%29%2F%283--1%29 Subtract 0 from 10 to get 10


m=%2810%29%2F%284%29 Subtract -1 from 3 to get 4


m=5%2F2 Reduce


So the slope of the line that goes through the points and is m=5%2F2


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-0=%285%2F2%29%28x--1%29 Plug in m=5%2F2, x%5B1%5D=-1, and y%5B1%5D=0


y-0=%285%2F2%29%28x%2B1%29 Rewrite x--1 as x%2B1


y=%285%2F2%29%28x%2B1%29 Simplify


2y=5%28x%2B1%29 Multiply both sides by 2.


2y=5x%2B5 Distribute.


-5x%2B2y=5 Subtract 5x from both sides.


5x-2y=-5 Multiply EVERY term by -1 to make the x coefficient positive.


So the equation in standard form is 5x-2y=-5


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim