SOLUTION: one x-intercept of a parabola is at a point of (1,0)use the factor method to find the other x-intercept defined by this equation: y=-5x^2+15x-10.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: one x-intercept of a parabola is at a point of (1,0)use the factor method to find the other x-intercept defined by this equation: y=-5x^2+15x-10.      Log On


   

Question 389251: one x-intercept of a parabola is at a point of (1,0)use the factor method to find the other x-intercept defined by this equation: y=-5x^2+15x-10.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

y=-5x^2+15x-10

Factoring to find the x-intercepts when y = 0

 -5x^2 + 15x  - 10 = 0

 -5(x^2 - 3x + 2) = 0

 -5(x-2)(x-1)=0 Note:SUM of the inner product(-2x) and the outer product(-x) = -  (x-1)=0 

    x = 1  As the question states and...

  (x-2)=0

    x = 2

Please note vertex (3/2, 5/4 )

found by completing square for y = -5x^2+15x-10 = -5(x-3/2)^2 + 5/4)

the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex