SOLUTION: A 48 cm long wire is bent to form a rectangle whose length is twice it's width. Find the length and area of this rectangle.
Algebra ->
Surface-area
-> SOLUTION: A 48 cm long wire is bent to form a rectangle whose length is twice it's width. Find the length and area of this rectangle.
Log On
Question 389189: A 48 cm long wire is bent to form a rectangle whose length is twice it's width. Find the length and area of this rectangle. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! A 48 cm long wire is bent to form a rectangle whose length is twice it's width. Find the length and area of this rectangle.
...
width x
length =2x
..
perimeter = 48
...
2*(L+W)=48
2*(2x+x)=48
/2
3x=24
/3
x= 8 cm the width.
length = 2x = 2*8=16 cms
more info write with email address
..
m.ananth@hotmail.ca
