SOLUTION: What are the solutions for the system of equations for x^2+y^2=36 y=x+2. I tried using substitution, but when it came down to the factoring part I got stuck.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What are the solutions for the system of equations for x^2+y^2=36 y=x+2. I tried using substitution, but when it came down to the factoring part I got stuck.      Log On


   

Question 389077: What are the solutions for the system of equations for x^2+y^2=36 y=x+2. I tried using substitution, but when it came down to the factoring part I got stuck.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1.x%5E2%2By%5E2=36
2.y=x%2B2
From eq. 2,
y%5E2=%28x%2B2%29%5E2
y%5E2=x%5E2%2B4x%2B4
Substitute into eq. 1,
x%5E2%2B%28x%5E2%2B4x%2B4%29=36
2x%5E2%2B4x-32=0
x%5E2%2B2x-16=0
%28x%5E2%2B2x%2B1%29-16-1=0
%28x%2B1%29%5E2-17=0
%28x%2B1%29%5E2=17
x%2B1=0++%2B-+sqrt%2817%29
highlight%28x=-1+%2B-+sqrt%2817%29%29
Then from eq. 2,
y=-1+%2B-+sqrt%2817%29%2B2
highlight%28y=1%2B-+sqrt%2817%29%29
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