SOLUTION: The line y = ax + 7 is parallel to the line y = 2x - 3. The line y = bx + 7 is perpendicular to the line y = 2x- 3.
a) State the value of a and of b.
b) Calculate the perpendicul
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-> SOLUTION: The line y = ax + 7 is parallel to the line y = 2x - 3. The line y = bx + 7 is perpendicular to the line y = 2x- 3.
a) State the value of a and of b.
b) Calculate the perpendicul
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Question 389037: The line y = ax + 7 is parallel to the line y = 2x - 3. The line y = bx + 7 is perpendicular to the line y = 2x- 3.
a) State the value of a and of b.
b) Calculate the perpendicular distance between the pair of parallel lines.
*Please solve this question and explain it in detail. Also explain your answers in as much detail as possible, especially part (b). Thanks :)* Answer by ewatrrr(24785) (Show Source):
Hi,
Note: the standard slope-intercept form for an equation of a line is y = mx + b
where m is the slope and b the y-intercept.
a) State the value of a and of b.
y = ax + 7 is parallel to the line y = 2x - 3 (lines have same slope)
a = 2 y = 2x + 7
The line y = bx + 7 is perpendicular to the line y = 2x- 3.
Perpendicular lines have Slopes that are negative reciprocals of one another:
b = -1/2 y = -.5x + 7
b) Calculate the perpendicular distance between the pair of parallel lines.
graphing
y = 2x - 3 and y = 2x + 7 and the line perpendicular to both: y = -.5x + 7
Distance between Pt(0,7) and Pt(4,5)would be:
