SOLUTION: A cook uses fifteen 2-kg bottles of cooking-oil over a 4-week period. If he decides to buy 5-kg tins of oil instead, how many tins of cooking oil will he use over a 10-week period

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Question 389013: A cook uses fifteen 2-kg bottles of cooking-oil over a 4-week period. If he decides to buy 5-kg tins of oil instead, how many tins of cooking oil will he use over a 10-week period if the rate of using it remains unchanged?
Answer by jerryguo41(197) About Me  (Show Source):
You can put this solution on YOUR website!
%2815+2-kg+bottles%29+%2F+%284-week+period%29+=+%28x+5-kg+tins%29+%2F+%2810-week+period%29
%2815%2A2%29%2F4+=+5x%2F10
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: x=15.
  • Graphical form: Equation %2815%2A2%29%2F4=5x%2F10 was fully solved.
  • Text form: (15*2)/4=5x/10 simplifies to 0=0
  • Cartoon (animation) form: simplify_cartoon%28+%2815%2A2%29%2F4=5x%2F10+%29
    For tutors: simplify_cartoon( (15*2)/4=5x/10 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at highlight_red%28+%28highlight_red%28+15%2A2+%29%29%2F4+%29=5x%2F10.
Remove unneeded parentheses around factor highlight_red%28+15+%29,highlight_red%28+2+%29
It becomes highlight_green%28+15+%29%2Ahighlight_green%28+2+%29%2F4=5x%2F10.
Look at 15%2Ahighlight_red%28+2+%29%2Fhighlight_red%28+4+%29=5x%2F10.
Factors 2 and 4 have greatest common factor (GCF) of 2. Reducing fraction.
It becomes 15%2Ahighlight_green%28+1+%29%2Fhighlight_green%28+2+%29=5x%2F10.
Look at highlight_red%28+15+%29%2Ahighlight_red%28+1+%29%2F2=5x%2F10.
Multiplied numerator integers
It becomes highlight_green%28+15+%29%2F2=5x%2F10.
Look at 15%2F2=highlight_red%28+5+%29%2Ax%2Fhighlight_red%28+10+%29.
Factors 5 and 10 have greatest common factor (GCF) of 5. Reducing fraction.
It becomes 15%2F2=highlight_green%28+1+%29%2Ax%2Fhighlight_green%28+2+%29.
Look at 15%2F2=highlight_red%28+1+%29%2Ax%2F2.
Remove extraneous '1' from product highlight_red%28+1+%29
It becomes 15%2F2=x%2F2.
Look at 15%2F2=highlight_red%28+x%2F2+%29.
Moved these terms to the left highlight_green%28+-x%2F2+%29
It becomes 15%2F2-highlight_green%28+x%2F2+%29=0.
Look at highlight_red%28+15%2F2+%29-x%2F2=0.
Moved 15%2F2 to the right of expression
It becomes -x%2F2%2Bhighlight_green%28+15%2F2+%29=0.
Look at highlight_red%28+-x%2F2%2B15%2F2+%29=0.
Solved linear equation highlight_red%28+-x%2F2%2B15%2F2=0+%29 equivalent to -0.5*x+7.5 =0
It becomes highlight_green%28+0+%29=0.
Result: 0=0
This is an equation! Solutions: x=15.

Universal Simplifier and Solver


Done!