SOLUTION: we have 2 boys and 4 girls to be seated in a 6-seat row at the movie theatre. What is the probability that the two people at the end of the row were both boys or both girls? Expres
Algebra ->
Probability-and-statistics
-> SOLUTION: we have 2 boys and 4 girls to be seated in a 6-seat row at the movie theatre. What is the probability that the two people at the end of the row were both boys or both girls? Expres
Log On
Question 388906: we have 2 boys and 4 girls to be seated in a 6-seat row at the movie theatre. What is the probability that the two people at the end of the row were both boys or both girls? Express your answer as a common fraction? Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! nPr=permutations of n things taken r at a time=n!/(n-r)!
Both boys=4!*2=48 ways
Both girls=4P2*4!=12*24=288 ways
(48+288)/6!=336/720=7/15
.
Ed
