Question 388709: Solve -3x^2+4=0 by using the Quadratic Formula.
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Answer by haileytucki(390)   (Show Source):
You can put this solution on YOUR website! -3x^(2)+4=0 (the ~ symbol stands for sgaure root of)
Multiply each term in the equation by -1.
-3x^(2)*-1+4*-1=0*-1
Simplify the left-hand side of the equation by multiplying out all the terms.
3x^(2)-4=0*-1
Multiply 0 by -1 to get 0.
3x^(2)-4=0
Use the quadratic formula to find the solutions. In this case, the values are a=3, b=0, and c=-4.
x=(-b\~(b^(2)-4ac))/(2a) where ax^(2)+bx+c=0
Use the standard form of the equation to find a, b, and c for this quadratic.
a=3, b=0, and c=-4
Substitute in the values of a=3, b=0, and c=-4.
x=(-0\~((0)^(2)-4(3)(-4)))/(2(3))
-0 is equal to 0.
x=(0\~((0)^(2)-4(3)(-4)))/(2(3))
Simplify the section inside the radical.
x=(0\4~(3))/(2(3))
Simplify the denominator of the quadratic formula.
x=(0\4~(3))/(6)
First, solve the + portion of +-.
x=(0+4~(3))/(6)
Combine all similar expressions.
x=(4~(3))/(6)
Reduce the expression (4~(3))/(6) by removing a factor of 2 from the numerator and denominator.
x=(2~(3))/(3)
Next, solve the - portion of +-
x=(0-4~(3))/(6)
Combine all similar expressions.
x=(-4~(3))/(6)
Move the minus sign from the numerator to the front of the expression.
x=-(4~(3))/(6)
Reduce the expression -(4~(3))/(6) by removing a factor of 2 from the numerator and denominator.
x=-(2~(3))/(3)
The final answer is the combination of both solutions.
x=(2~(3))/(3),-(2~(3))/(3)_x=1.154701,-1.154701
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