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Question 388706: Solve 3√x+2=6√9x+10
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Answer by haileytucki(390)   (Show Source):
You can put this solution on YOUR website! 3~(x+2)=6~(9x+10) The ~stands for the square root of in this equation.
To remove the radical on the left-hand side of the equation, square both sides of the equation.
(3~(x+2))^(2)=(6~(9x+10))^(2)
Simplify the left-hand side of the equation.
(3)^(2)(x+2)=(6~(9x+10))^(2)
Expand the exponent of 2 to each factor in the expression 6~(9x+10).
(3)^(2)(x+2)=36(9x+10)
Multiply 36 by each term inside the parentheses.
(3)^(2)(x+2)=324x+360
Expand the exponent (2) to the expression.
3^(2)(x+2)=324x+360
Squaring a number is the same as multiplying the number by itself (3*3). In this case, 3 squared is 9.
9(x+2)=324x+360
Multiply 9 by each term inside the parentheses.
9x+18=324x+360
Since 324x contains the variable to solve for, move it to the left-hand side of the equation by subtracting 324x from both sides.
9x+18-324x=360
Since 9x and -324x are like terms, add -324x to 9x to get -315x.
-315x+18=360
Since 18 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 18 from both sides.
-315x=-18+360
Add 360 to -18 to get 342.
-315x=342
Divide each term in the equation by -315.
-(315x)/(-315)=(342)/(-315)
Simplify the left-hand side of the equation by canceling the common factors.
x=(342)/(-315)
Simplify the right-hand side of the equation by simplifying each term.
x=-(38)/(35)
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