SOLUTION: Need your help please! In the interval 0° ≤ θ ≤ 360°, how many values of θ satisfy the equation {{{Tan^2theta-3Tan(theta) + 2}}}{{{""=""}}}{{{0}}} ? a)

Algebra ->  Trigonometry-basics -> SOLUTION: Need your help please! In the interval 0° ≤ θ ≤ 360°, how many values of θ satisfy the equation {{{Tan^2theta-3Tan(theta) + 2}}}{{{""=""}}}{{{0}}} ? a)      Log On


   



Question 388645: Need your help please!
In the interval 0° ≤ θ ≤ 360°, how many values of θ satisfy the equation Tan%5E2theta-3Tan%28theta%29+%2B+2%22%22=%22%220
?
a)1
b)2
c)3
d)4
Thanks

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Need your help please!
In the interval 0° ≤ θ ≤ 360°, how many values of θ satisfy the equation
Tan%5E2theta-3Tan%28theta%29+%2B+2+=+0
a)1
b)2
c)3
d)4
Tan%5E2theta-3Tan%28theta%29+%2B+2%22%22=%22%220

Factor the left side:

%28Tan%28theta%29-+2%29%28Tan%28theta%29-1%29%22%22=%22%220

Use the zero-factor principle:

Tan%28theta%29-2%22%22=%22%220
Tan%28theta%29%22%22=%22%222

Since the tangent is positive in the first and third quadrants,
there are two angles between 0° and 360° that have 2 as their 
tangent.  These are 63.43° and 243.43° approximately

Continuing with the zero-factor principle:

Tan%28theta%29-1%22%22=%22%220
Tan%28theta%29%22%22=%22%221
 
Again, since the tangent is positive in the first and third quadrants,
there are two angles between 0° and 360° that have 1 as their 
tangent.  These are 45° and 225° exactly.

So the answer is d)4

Edwin