Question 38853This question is from textbook Beginning Algebra
: Okay, I added, but am having trouble simplifiying...
could you please help me?
This is what I have so far...
x² 3x - 70
———————— + —————————
x + 10 x + 10
I got
x² + 3x - 70
——————————————
x + 10
how do I simplify that?
Thank you in advance for your help.
This question is from textbook Beginning Algebra
Found 2 solutions by fractalier, AnlytcPhil:
Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website! Okay from
x^2 / x+10 + 3x-70 / x+10
we can add the numerator as they are since the denominators are the same, or what are called "like" denominators, so we simply get
(x^2 + 3x - 70) / (x + 10)
Now we factor the numerator and get
(x + 10)(x - 7) / (x + 10)
oh, what a surprise, the x + 10's cancel, leaving
the answer: x - 7
Answer by AnlytcPhil(1807)  (Show Source):
You can put this solution on YOUR website! Okay, I added, but am having trouble simplifying
...could you please help me?
This is what I have so far...
x² 3x - 70
———————— + —————————
x + 10 x + 10
Since these fraction terms already have the same
denominator, we simply combine their numerators
and write it over this
common denominator:
x² + (3x - 70)
————————————————
(x + 10)
x² + 3x - 70
——————————————
(x + 10)
This is how far you got.
Here's the rest:
Factor the numerator
(x + 10)(x - 7)
—————————————————
(x + 10)
Cancel the (x + 10)'s
1
(x + 10)(x - 7)
—————————————————
(x + 10)
1
x - 7
Edwin
AnlytcPhil@aol.com
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