SOLUTION: how much pure acid must be added to 6 milliliters of a 5% acid solution to produce a 40% acid solution?
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Question 38833
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how much pure acid must be added to 6 milliliters of a 5% acid solution to produce a 40% acid solution?
Answer by
checkley71(8403)
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.05*6+X=.4(6+X) OR .3+X=2.4+.4X OR .6X=2.1 OR X=2.1/6 OR X=3.5 LITERS OF PURE ACID NEEDS TO BE ADDED.