SOLUTION: Find the measure of the three angles of a triangle if the smallest angle is one- sixth of the largest and the other angle is twice the smallest angle.

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Question 388303: Find the measure of the three angles of a triangle if the smallest angle is one- sixth of the largest and the other angle is twice the smallest angle.
Found 3 solutions by solver91311, ewatrrr, lwsshak3:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


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Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,         

Let x, 2x and 6x represent the smallest angles and larger two angles respectively

question states***

  x + 2x + 6x = 180°

solving for x

          9x = 180°

           x = 20°, the smallest, the others 40° and 120°



CHECKING our Answer

  20° + 40° + 120° = 180°

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
let x = smallest angle of triangle
then, 6x = largest angle
and 2x = other angle
fact: the three angles of a triangle total 180 deg
therefore, x+2x+6x=180
or 9x=180
dividing both sides of the equation by 9,
x=20
ans: the smallest angle of the triangle is 20 deg