SOLUTION: How many different three-number "combinations" are possible on a combination lock having 25 numbers on its dial with out repeating a number?

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Question 38820: How many different three-number "combinations" are possible on a combination lock having 25 numbers on its dial with out repeating a number?
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
C(25,3) = 25!/((22!)(3!)) = 2300
2300 different combinations.