SOLUTION: How do I solve xy^2 over x^2y divided by x over y^3 ? Ex. 3x over 5y divided by 21x over 2y = 3x over 5y times 2y over 21x = 6xy over 105xy = 2 over 35

Algebra ->  Rational-functions -> SOLUTION: How do I solve xy^2 over x^2y divided by x over y^3 ? Ex. 3x over 5y divided by 21x over 2y = 3x over 5y times 2y over 21x = 6xy over 105xy = 2 over 35      Log On


   

Question 388196:
How do I solve xy^2 over x^2y divided by x over y^3 ?
Ex. 3x over 5y divided by 21x over 2y = 3x over 5y times 2y over 21x = 6xy over 105xy = 2 over 35
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify first,
%28xy%5E2%29%2F%28x%5E2y%29=x%5E%281-2%29y%5E%282-1%29=x%5E%28-1%29y%5E%281%29=y%2Fx
.
.
So then,
%28%28xy%5E2%29%2F%28x%5E2y%29%29%2F%28x%2Fy%5E3%29=%28y%2Fx%29%2A%28y%5E3%2Fx%29
.
.
%28%28xy%5E2%29%2F%28x%5E2y%29%29%2F%28x%2Fy%5E3%29=highlight%28y%5E4%2Fx%5E2%29