SOLUTION: log(7x+1)=log(x-2)+ 1

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: log(7x+1)=log(x-2)+ 1      Log On


   

Question 387834: log(7x+1)=log(x-2)+ 1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,         

 log(7x+1)-log(x-2)= 1







  10^1 = (7x+1)/(x-2)

  10(x-2) = 7x+1

  10x -20 = 7x + 1

       3x = 21

        x = 7