SOLUTION: Given the linear equation Y=-1/3X+6, find the y-coordinates of the points (-9, ), (-3, ), and (6, ). Please show all of your work. Plot those points and graph the linear equatio

Algebra ->  Inequalities -> SOLUTION: Given the linear equation Y=-1/3X+6, find the y-coordinates of the points (-9, ), (-3, ), and (6, ). Please show all of your work. Plot those points and graph the linear equatio      Log On


   

Question 387564: Given the linear equation Y=-1/3X+6, find the y-coordinates of the points (-9, ), (-3, ), and (6, ). Please show all of your work. Plot those points and graph the linear equation. Submit your graph through the dropbox. ANYONE CAN HELP PLZZZ!!!
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,         

  y = -(1/3)x + 6 

Finding the y-coordinates of -9,-3, 6 by substitutng these values for x.

  y = -(1/3)*-9 + 6  = 9    Pt(-9,9)

  y = -(1/3)*-3 + 6  = 7    Pt(-3,7)

  y = -(1/3)*6 + 6   = 4    Pt(6,4)