SOLUTION: solve for x: 〖log〗_2 x=〖log〗_2 (x^2-6)

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Question 387559: solve for x:
〖log〗_2 x=〖log〗_2 (x^2-6)
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
log%282%2Cx%29+=+log%282%2Cx%5E2-6%29
x+=+x%5E2-6
0+=+x%5E2-x-6
factoring:
0+=+%28x-3%29%28x%2B2%29
x = {-2, 3}
But, testing for extraneous solutions, we throw out the negative solution leaving:
x = 3