SOLUTION: When a ball is thrown, its height in feet "h" after "t" seconds is given by the equation
h = vt - 16t^2.
In this equation, "v" is the initial upwards velocity in feet per second.
Algebra ->
Expressions-with-variables
-> SOLUTION: When a ball is thrown, its height in feet "h" after "t" seconds is given by the equation
h = vt - 16t^2.
In this equation, "v" is the initial upwards velocity in feet per second.
Log On
Question 38731: When a ball is thrown, its height in feet "h" after "t" seconds is given by the equation
h = vt - 16t^2.
In this equation, "v" is the initial upwards velocity in feet per second. If v=28 feet per second, find all values of "t" for which h=12 feet. Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! Let us substitute the values as given and then solve for t...
h = vt - 16t^2
12 = 28t - 16t^2
16t^2 - 28t + 12 = 0
4t^2 - 7t + 3 = 0
(4t - 1)(t - 3) = 0
Thus
t = 1/4 sec and t = 3 sec
