SOLUTION: Write the slope-intercept equation for the line that passes through (-8, -11) and is perpendicular to -2x – 7y = -14

Algebra ->  Linear-equations -> SOLUTION: Write the slope-intercept equation for the line that passes through (-8, -11) and is perpendicular to -2x – 7y = -14       Log On


   

Question 387244: Write the slope-intercept equation for the line that passes through (-8, -11) and is perpendicular to -2x – 7y = -14
Answer by gwendolyn(128) About Me  (Show Source):
You can put this solution on YOUR website!
The equation for slope-intercept form is:
y=mx+b
First, we need to find the slope for the original line.
We'll put the line into y=mx+b form:
-2x-7y=-14
-7y=2x-14
y=-2%2F7x+2
Now, we have the slope of the original line. To find the perpendicular slope, we just find the negative reciprocal-- 7%2F2
The new line has a slope, but no y intercept.
We'll plug in the values of x and y that have been supplied to find our 'b'.
y=mx+b
-11=%287%2F2%29%2A-8%2Bb
-11=-28%2Bb
17=b
Therefore, b is 17
Finally, we know the perpendicular line's slope and y intercept. Therefore, we can make a slope intercept equation for the perpendicular line.
y=mx+b
y=7%2F2x+17