SOLUTION: A PURSE CONTAINS $2.45 IN NICKLES AND DIMES. IF THERE ARE 32 COINS ALL TOGETHER USE ALGEBRA TO FIND HOW MANY NICKLES ARE IN THE PURSE.

Algebra ->  Average -> SOLUTION: A PURSE CONTAINS $2.45 IN NICKLES AND DIMES. IF THERE ARE 32 COINS ALL TOGETHER USE ALGEBRA TO FIND HOW MANY NICKLES ARE IN THE PURSE.      Log On


   

Question 387085: A PURSE CONTAINS $2.45 IN NICKLES AND DIMES. IF THERE ARE 32 COINS ALL TOGETHER USE ALGEBRA TO FIND HOW MANY NICKLES ARE IN THE PURSE.
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

Let N be the number of nickels, D the number of dimes.
1.N%2BD=32
.
.
5N%2B10D=245
2.N%2B2D=49
Subtract eq. 1 from eq. 2,
N%2B2D-N-D=49-32
highlight%28D=17%29
Then from eq. 1,
N%2B17=32
highlight%28N=15%29

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

THERE ARE 32 COINS ALL TOGETHER 

Let x and (32-x) represent the number of dimes and nickels respectively

 Question states:

 10x + 5(32-x) = 245 cents

        5x = 245 - 5*32

        5x = 85

         x = 17, the number of dimes.  Number of nickels is 15   (32-17)

CHECKING our Answer

    10*17 + 5*15 = 170 + 75 = 245 cents OR $2.45