SOLUTION: solve for x: log x + log(x-1) = log(4x)
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Question 387079
:
solve for x:
log x + log(x-1) = log(4x)
Answer by
nerdybill(7384)
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log x + log(x-1) = log(4x)
log x(x-1) = log(4x)
x(x-1) = (4x)
x^2-x = 4x
x^2-5x = 0
x(x-5) = 0
x = {0,5}
Testing for "extraneous solutions" we must toss out 0 leaving:
x = 5