Question 386857: write an equation for the hyperbola that satisfies each set of conditions. vertices (0,-4) and (0,4), conjugate axis of length 14 units Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Standard forms of a hyperbola
(x-h)^2/a^2-(y-k)^2/b^2 = 1 (transverse axis horizontal)
(y-k)^2/a^2-(x-h)^2/b^2 = 1 (transverse axis vertical)
coordinates of given vertices show that transverse axis vertical with center of hyperbola at the origin (0,0)
this also means the y-term comes first, and h=0 and k=0
transverse axis, 8=2a
a=4
a^2=16
from given conjugate axis, 14=2b
b=7
b^2=49
ans: equation of hyperbola, y^2/16-x^2/49 =1
see the following graph
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