SOLUTION: Please help. I'm confused on how to do this. Suppose a polynomial P(x) when divided by x-9 has a quotient of 4x^3+5x^2+7x+13 and a remainder of 88. Find P(9).

Algebra ->  Test -> SOLUTION: Please help. I'm confused on how to do this. Suppose a polynomial P(x) when divided by x-9 has a quotient of 4x^3+5x^2+7x+13 and a remainder of 88. Find P(9).       Log On


   

Question 386848: Please help. I'm confused on how to do this.
Suppose a polynomial P(x) when divided by x-9 has a quotient of 4x^3+5x^2+7x+13 and a remainder of 88. Find P(9).
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
The statement implies that

P%28x%29+=+%28x-9%29%284x%5E3+%2B+5x%5E2+%2B+7x+%2B+13%29+%2B+88

Therefore, P(9) = 88.