SOLUTION: The equation below is a circle. What is the x-coordinate of the center of the circle? (x - 6)2 + (y + 5)2 = 152

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: The equation below is a circle. What is the x-coordinate of the center of the circle? (x - 6)2 + (y + 5)2 = 152      Log On


   

Question 386560: The equation below is a circle. What is the x-coordinate of the center of the circle?
(x - 6)2 + (y + 5)2 = 152
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2

 (x - 6)^2 + (y + 5)^2 = 152

 Center is Pt(6,-5)  radius is sqrt(152) = 12.38