SOLUTION: Let x and y be real numbers. If (x+yi) - (2-3i) = -6+4i, what are the values of x and y? a) x=8, y=7 b) x=8, y=1 c) x=-4, y=7 d) x=-4, y=1

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Let x and y be real numbers. If (x+yi) - (2-3i) = -6+4i, what are the values of x and y? a) x=8, y=7 b) x=8, y=1 c) x=-4, y=7 d) x=-4, y=1      Log On


   

Question 386558: Let x and y be real numbers. If (x+yi) - (2-3i) = -6+4i, what are the values of x and y?
a) x=8, y=7
b) x=8, y=1
c) x=-4, y=7
d) x=-4, y=1
Answer by sudhanshu_kmr(1152) About Me  (Show Source):
You can put this solution on YOUR website!

(x + yi)- (2-3i) = -6 + 4i
=> x-2 + i(y+3) = -6 + 4i

by comparing real and imaginary part ........
x = -6 + 2 = -4
y = 4 -3 = 1

(d) is correct ......