Question 386491: An ordinary die is tossed four times. What is the probability of obtaining a number greater than 4 at least once? Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! First, let's compute the probability that after four rolls, all numbers are less than or equal to four. After that, we can subtract from 1 since the rest of the cases involve a number being greater than 4 at least once.
The probability that no number exceeds 4 is
1 - (16/81) = 65/81, which is the final probability.
