SOLUTION: write the standard form of the equation of a line that is perpendicular to the graph of the given equation and passes through the point with the given coordinates 4x-2y+2=0; (1,4)

Algebra ->  Linear-equations -> SOLUTION: write the standard form of the equation of a line that is perpendicular to the graph of the given equation and passes through the point with the given coordinates 4x-2y+2=0; (1,4)      Log On


   

Question 386136: write the standard form of the equation of a line that is perpendicular to the graph of the given equation and passes through the point with the given coordinates 4x-2y+2=0; (1,4)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Line perpendicular to 4x-2y+2=0  OR y = 2x+1  slope = 2

New line will have a slope = -1/2  (negative reciprocal of 2)

the standard 'slope-intercept form' for an equation of a line: y = mx + b 

 where m is the slope and b the y-intercept.  

y = -.5x + b Using ordered pair Pt(1,4) to solve for b

 4 = -.5*1 + b

 4.5 = b

y = -.5x + 4.5  OR   5x + 10y = 45 (in standard from)