SOLUTION: The probability that a house in an urban area will be burglarized is 8.5%. If 45 houses are randomly selected, what is the probability that four of the houses will be burglarized?

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Question 386083: The probability that a house in an urban area will be burglarized is 8.5%. If 45 houses are randomly selected, what is the probability that four of the houses will be burglarized?
(a) Is this a binomial experiment? Explain how you know.
(b) Use the correct formula to find the probability that, out of 45 houses, exactly 4 of the houses will be burglarized. Show your calculations or explain how you found the probability

Found 2 solutions by stanbon, edjones:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The probability that a house in an urban area will be burglarized is 8.5%. If 45 houses are randomly selected, what is the probability that four of the houses will be burglarized?
(a) Is this a binomial experiment? Explain how you know.
There are 2 outcomes; burgled or not
P(burgled) is the same for each house.
The burgles are independent.
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(b) Use the correct formula to find the probability that, out of 45 houses, exactly 4 of the houses will be burglarized. Show your calculations or explain how you found the probability
P(x = 4) = 45C4(0.085)^4*(0.91.5)^41 = binompdf(45,0.085,4) = 0.2038
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Cheers,
Stan H.
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Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Combination=nCr=comcination of n things taken r at a time=n!/((n-r)!r!)
a) yes
.
b)
45C4=148995
148995*x^4*y^41 when x=.085 and y=.915
=.2038
.
Ed