SOLUTION: David recently switched to a long distance phone company which charges a monthly fee of $5.95 plus $0.04 per minute. A linear function that expresses the monthly bill B as a funct
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-> SOLUTION: David recently switched to a long distance phone company which charges a monthly fee of $5.95 plus $0.04 per minute. A linear function that expresses the monthly bill B as a funct
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Question 385962: David recently switched to a long distance phone company which charges a monthly fee of $5.95 plus $0.04 per minute. A linear function that expresses the monthly bill B as a function of minutes used is B(m) = 0.04m + 5.95. How many minutes were used for long distance if the long-distance phone bill was $17.15? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! David recently switched to a long distance phone company which charges a monthly fee of $5.95 plus $0.04 per minute. A linear function that expresses the monthly bill B as a function of minutes used is B(m) = 0.04m + 5.95. How many minutes were used for long distance if the long-distance phone bill was $17.15?
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B(m) = 0.04m + 5.95
Bill = 17.15
17.15=0.04m+5.95
..
17.15-5.95=0.04m
11.20=0.04m
/0.04
11.20/0.04=m minutes
...
m.ananth@hotmail.ca
